How can I correctly send actual parameters of integers to main to calculate the sum in C++?

The books tells me The declaration of the main looks like this:

int main(int argc, char* argv[])

or int main(int argc, char** argv)

It seems that int argc, char** argv are the only things I can send as actual parameters.

Now I don't want to deal with strings main.

I want to calculate the sum of integers sent to main and return the sum.

#include <iostream> int main(int n, char** argv) {         std::cout << n << std::endl;         char** temp = argv;         int sum = 0;         int i = 0;         while (*temp != NULL) {                 std::cout << i++ << ':' << *temp << std::endl;                 sum += *temp++;         }         return 0; }

The above is my original thinking that fails to work.

I think argument must be array of argc of pointer to integer. So following is the updated code:

#include <iostream> int main(int n, int* argv[]) {         std::cout << n << std::endl; //print the number of the arguments passed         int** temp = argv;         int sum = 0;         int i = 0;         while (*temp != NULL) {                 std::cout << i++ << ':' << **temp << std::endl;                 if (*temp != argv[0])                         sum += **temp;                 ++temp;         }         std::cout << "The sum of all integered entered is " << sum << std::endl;         return 0; }

After compiling the code with GCC, I enter ./a.out 1 2 3, and I get

4

0:778121006

1:3276849

2:3342386

3:1213399091

The sum of all integered entered is 1220018326

I know it is far from perfect but it is better than the first one.

I think temp(or argv) is degraded to pointer to a pointer to an integer. 

So **temp should be an integer. 

Why the print of **temp looks like a pointer?

How can I correctly send actual parameters of integers to main to calculate the sum?